document.write( "Question 71145: Two ln problems I need help with.\r
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document.write( "ln 3 - (ln x + ln 6) = ln x - ln 8\r
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document.write( "ln 3 + ln 2x = 7\r
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document.write( "Please help!
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document.write( "Thanks!! \n" );
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Algebra.Com's Answer #50863 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! ln 3 - (ln x + ln 6) = ln x - ln 8\r \n" ); document.write( "\n" ); document.write( "ln3 - (ln6x) = ln(x/8)\r \n" ); document.write( "\n" ); document.write( "ln(3/6x) = ln(x/8)\r \n" ); document.write( "\n" ); document.write( "1/2x = x/8 \n" ); document.write( "2x^2 = 8 \n" ); document.write( "x^2=4\r \n" ); document.write( "\n" ); document.write( "x=2. \n" ); document.write( "------------------\r \n" ); document.write( "\n" ); document.write( "ln 3 + ln 2x = 7\r \n" ); document.write( "\n" ); document.write( "ln(6x)=7 \r \n" ); document.write( "\n" ); document.write( "e^7 = 6x \n" ); document.write( "6x = 1096.63\r \n" ); document.write( "\n" ); document.write( "x=182.77\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |