document.write( "Question 844137: \r
\n" ); document.write( "\n" ); document.write( "One car travels 165 miles in the same amount of time it takes a second car traveling 3 miles per hour slower than the first to go 156 miles. What are the speeds of the cars?
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Algebra.Com's Answer #508624 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
DIST=SPEED*TIME
\n" ); document.write( "165=S*T
\n" ); document.write( "156=(S-3)T
\n" ); document.write( "S=165/T
\n" ); document.write( "156=(165/T-3)T
\n" ); document.write( "156=165-3T
\n" ); document.write( "3T=165-156
\n" ); document.write( "3T=9
\n" ); document.write( "T=9/3
\n" ); document.write( "T=3 HOURS.
\n" ); document.write( "165=S*3
\n" ); document.write( "S=165/3
\n" ); document.write( "S=55 MPH. FOR THE FASTER TRUCK
\n" ); document.write( "55-3=52 MPH FOR THE SLOWER TRUCK
\n" ); document.write( "PROOF:
\n" ); document.write( "156=52*3
\n" ); document.write( "156=156
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