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document.write( "One car travels 165 miles in the same amount of time it takes a second car traveling 3 miles per hour slower than the first to go 156 miles. What are the speeds of the cars? \n" );
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Algebra.Com's Answer #508624 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! DIST=SPEED*TIME \n" ); document.write( "165=S*T \n" ); document.write( "156=(S-3)T \n" ); document.write( "S=165/T \n" ); document.write( "156=(165/T-3)T \n" ); document.write( "156=165-3T \n" ); document.write( "3T=165-156 \n" ); document.write( "3T=9 \n" ); document.write( "T=9/3 \n" ); document.write( "T=3 HOURS. \n" ); document.write( "165=S*3 \n" ); document.write( "S=165/3 \n" ); document.write( "S=55 MPH. FOR THE FASTER TRUCK \n" ); document.write( "55-3=52 MPH FOR THE SLOWER TRUCK \n" ); document.write( "PROOF: \n" ); document.write( "156=52*3 \n" ); document.write( "156=156 \n" ); document.write( " |