document.write( "Question 844201: the length of a rectangle is 2cm more than 3 times the width. the area is 16Cm.find the length and the width.let x=be the width \n" ); document.write( "
Algebra.Com's Answer #508618 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! L=3X+2 \n" ); document.write( "AREA=LX \n" ); document.write( "16=(3X+2)X \n" ); document.write( "16=X^2+2X \n" ); document.write( "3X^2+2X-16=0 \n" ); document.write( "(X+8)X-2)=0 \n" ); document.write( "X-2=0 \n" ); document.write( "X=2 CM. ANS. FOR THE WIDTH \n" ); document.write( "PROOF: \n" ); document.write( "16=(3*2+2)2 \n" ); document.write( "16=(6+2)2 \n" ); document.write( "16=8*2 \n" ); document.write( "16=16 \n" ); document.write( " \n" ); document.write( " |