document.write( "Question 844201: the length of a rectangle is 2cm more than 3 times the width. the area is 16Cm.find the length and the width.let x=be the width \n" ); document.write( "
Algebra.Com's Answer #508618 by checkley79(3341)\"\" \"About 
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L=3X+2
\n" ); document.write( "AREA=LX
\n" ); document.write( "16=(3X+2)X
\n" ); document.write( "16=X^2+2X
\n" ); document.write( "3X^2+2X-16=0
\n" ); document.write( "(X+8)X-2)=0
\n" ); document.write( "X-2=0
\n" ); document.write( "X=2 CM. ANS. FOR THE WIDTH
\n" ); document.write( "PROOF:
\n" ); document.write( "16=(3*2+2)2
\n" ); document.write( "16=(6+2)2
\n" ); document.write( "16=8*2
\n" ); document.write( "16=16
\n" ); document.write( "
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