document.write( "Question 844196: A new edition of a video game cost $60, but its previous version only cost $40. If 15 games are sold for $840, how many copies of the newest game sold?\r
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Algebra.Com's Answer #508601 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Maybe a mixture problem but also a linear system problem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n is how many new \n" ); document.write( "p is how many previous versions\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Account for total versions sold: \n" ); document.write( "Account for sales value: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SOLVE THE SYSTEM: \n" ); document.write( "---------------------- \n" ); document.write( "n+p=15 \n" ); document.write( "---------------------- \n" ); document.write( "3n+2p=42 \n" ); document.write( "----------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Choosing Elimination Method, you can use 2n+2p=30 and 3n+2p=42, and subtract first equation from second equation. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |