document.write( "Question 844170: please help me solve this:
\n" ); document.write( "on a certain trip, edgar drive 231 km in exactly the same time as erwin drive 308 km. If Erwin's rate exceeded that of edgar by 13 kph. Determine the rate of Erwin
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Algebra.Com's Answer #508590 by algebrahouse.com(1659)\"\" \"About 
You can put this solution on YOUR website!
Distance = rate x time\r
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\n" ); document.write( "\n" ); document.write( "distance
\n" ); document.write( "-------- = time
\n" ); document.write( "rate\r
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\n" ); document.write( "\n" ); document.write( "231
\n" ); document.write( "--- = Edgar's time
\n" ); document.write( "r\r
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\n" ); document.write( "\n" ); document.write( "308
\n" ); document.write( "------ = Erwin's time {Erwin's rate exceeded Edgar's by 13 kph}
\n" ); document.write( "r + 13\r
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\n" ); document.write( "\n" ); document.write( "231/r = 308/(r + 13) {their times were equal}
\n" ); document.write( "231r + 3003 = 308r {cross-multiplied in the proportion}
\n" ); document.write( "3003 = 77r {subtracted 231r from each side}
\n" ); document.write( "r = 39 {divided each side by 77}
\n" ); document.write( "r + 13 = 52 {substituted 39, in for r, into r + 13}\r
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\n" ); document.write( "\n" ); document.write( "Erwin's rate was 52 kph
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For more help from me, visit: www.algebrahouse.com


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