document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=844119>Question 844119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sepertate $90 into two parts so that the second part is $30 less than twice the first part. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #508579 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=508579\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = first part<BR>\n" );
document.write( "2x - 30 = second part {second part is 30 less than twice first}\r<BR>\n" );
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document.write( "x + 2x - 30 = 90 {the two parts add together to equal 90}<BR>\n" );
document.write( "3x - 30 = 90 {combined like terms}<BR>\n" );
document.write( "3x = 120 {added 30 to each side}<BR>\n" );
document.write( "x = 40 {divided each side by 3}<BR>\n" );
document.write( "2x - 30 = 50 {substituted 40, in for x, into 2x - 30}\r<BR>\n" );
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document.write( "40 and 50 are the two parts<BR>\n" );
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