document.write( "Question 71133: how do I solve the following formula:\r
\n" );
document.write( "\n" );
document.write( "4X Squared + 70X = -150\r
\n" );
document.write( "\n" );
document.write( "thank you\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #50856 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 4X^2+70X=-150 \n" ); document.write( "4X^2+70X+150=0 the process here is that you have to factor both the 4 & the 150 so that the sum of the products = 70. thus the factors of 4 are 1&4, 2&2. the factors of 150 are 1&150, 2&75, 3&50, 5&30, 6&25, 10&15. \n" ); document.write( "examples of the sum of products are: 2*2+2*75=4+150=154, 1*6+4*25=6+100=106, \n" ); document.write( "2*10+2*15=20+30=50 & 1*10+4*15=10+60=70 which is the pair of factors you want. \n" ); document.write( "hope this explains what needs to be done. it is a trial & error process or you could use the quadratic equation: \n" ); document.write( " \n" ); document.write( "(4X+10)(X+15)=0 \n" ); document.write( "4X+10=0 \n" ); document.write( "4X=-10 \n" ); document.write( "X=-10/4 \n" ); document.write( "X=-2.5 ANSWER \n" ); document.write( "X+15=0 \n" ); document.write( "X=-15 ANSWER \n" ); document.write( " \n" ); document.write( " |