document.write( "Question 71013: Solve the following systems by substitution.\r
\n" ); document.write( "\n" ); document.write( "8x - 4y = 16
\n" ); document.write( " y = 2x - 4
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Algebra.Com's Answer #50855 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "OK. From Eq 2, y=2x-4. So, lets substitute 2x-4 for y in Eq 1:\r
\n" ); document.write( "\n" ); document.write( "8x-4(2x-4)=16 get rid of parens\r
\n" ); document.write( "\n" ); document.write( "8x-8x+16=16 subtract 16 from both sides:\r
\n" ); document.write( "\n" ); document.write( "0=0\r
\n" ); document.write( "\n" ); document.write( "NO SOLUTION EXISTS. WHY??????????? Eq 1 and Eq 2 are identical equations\r
\n" ); document.write( "\n" ); document.write( "First, we'll multiply Eq 2 by 4 and we get:\r
\n" ); document.write( "\n" ); document.write( "4y=8x-16 rearrange this equation by subtracting 4y and adding 16 to both sides\r
\n" ); document.write( "\n" ); document.write( "8x-4y=16-------------SAME AS EQ 1\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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