document.write( "Question 844067: Find the length and width of a rectangle whose perimeter is 24 feet and whose area is 35 square feet. \n" ); document.write( "

Algebra.Com's Answer #508525 by nanakwame(5) $\"\"$ $\"About$

You can put this solution on YOUR website!
let the length=l
\n" ); document.write( "let the width=w
\n" ); document.write( "perimeter of a rectangle=2l 2w
\n" ); document.write( "area of a rectangle =l×w
\n" ); document.write( "2l 2l=24~(1)
\n" ); document.write( "l×w=35~(2)
\n" ); document.write( "w=35/l~(3)
\n" ); document.write( "put equation (3) into equation (1)
\n" ); document.write( "2l 2(35/l)=24
\n" ); document.write( "2l 70/l=24
\n" ); document.write( "2l^2 70=24l
\n" ); document.write( "l^2-12l 35=0
\n" ); document.write( "l=5,7
\n" ); document.write( "when l=7,w=5\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );