document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71107>Question 71107</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x + 7 = x^2 + k = 7x + 15 \r<BR>\n" );
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document.write( "That's the question. It has 2 (=) signs, how do you solve for k? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50845 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50845\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+7=7x+15<BR>\n" );
document.write( "3x-7x=15-7<BR>\n" );
document.write( "-4x=8<BR>\n" );
document.write( "x=8/-4<BR>\n" );
document.write( "x=-2 now substitute -2 for x in the middle equation<BR>\n" );
document.write( "-2^2+k=7*-2+15<BR>\n" );
document.write( "4+k=-14+15<BR>\n" );
document.write( "k=-14+15-4<BR>\n" );
document.write( "k=-3 answer.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "3*-2+7= -2^2-3<BR>\n" );
document.write( "-6+7=4-3<BR>\n" );
document.write( "1=1<BR>\n" );
document.write( " </SPAN>\n" );
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