document.write( "Question 71067: Factor completely: 27x^6-8y^9 \n" ); document.write( "
Algebra.Com's Answer #50839 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Factor completely: 27x^6 - 8y^9 \n" ); document.write( ": \n" ); document.write( "Factor as the difference of cubes: (x^3 - y^3) = (x - y)(x^2 + xy + y^2) \n" ); document.write( ": \n" ); document.write( "That would be: (27x^6 - 8y^9) = (3x^2 - 2y^3) (9x^4 + 3x^2*2y^3 + 4y^6) \n" ); document.write( ": \n" ); document.write( "Or: (27x^6 - 8y^9) = (3x^2 - 2y^3) (9x^4 + 6x^2y^3 + 4y^6) \n" ); document.write( " \n" ); document.write( " |