document.write( "Question 843889: A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present age \n" ); document.write( "
Algebra.Com's Answer #508388 by lwsshak3(11628)\"\" \"About 
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A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present age.
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\n" ); document.write( "let x=son's present age
\n" ); document.write( "2x=father's present age
\n" ); document.write( "..
\n" ); document.write( "12 years ago:
\n" ); document.write( "x-12=son's age
\n" ); document.write( "2x-12= father's age
\n" ); document.write( "2x-12=4(x-12)
\n" ); document.write( "2x-12=4x-48
\n" ); document.write( "2x=36
\n" ); document.write( "x=18
\n" ); document.write( "2x=36
\n" ); document.write( "son's present age=18
\n" ); document.write( "father's present age=36
\n" ); document.write( "
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