document.write( "Question 843889: A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present age \n" ); document.write( "
Algebra.Com's Answer #508388 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present age. \n" ); document.write( "*** \n" ); document.write( "let x=son's present age \n" ); document.write( "2x=father's present age \n" ); document.write( ".. \n" ); document.write( "12 years ago: \n" ); document.write( "x-12=son's age \n" ); document.write( "2x-12= father's age \n" ); document.write( "2x-12=4(x-12) \n" ); document.write( "2x-12=4x-48 \n" ); document.write( "2x=36 \n" ); document.write( "x=18 \n" ); document.write( "2x=36 \n" ); document.write( "son's present age=18 \n" ); document.write( "father's present age=36 \n" ); document.write( " |