document.write( "Question 843854: isosceles trapezoid with a perimeter of 52 yards; the measure if one base is 10 yards greater than the other base, the measure of each leg is 3 yards less than twice the length of the shorter base, Find the area of the figure \n" ); document.write( "
Algebra.Com's Answer #508360 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! A drawing helps, and is difficult to do through this system; so here is a description of the drawing:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let b = the shorter base. \n" ); document.write( "Longer base is b+10. \n" ); document.write( "Each nonparallel side of the trapezoid is 2b-3, and the trapezoid has two of them.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The perimeter is then \n" ); document.write( "Omitting the steps,... the solution here is \n" ); document.write( "The smaller base is 8 yards and the larger base is 18 yards.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Each nonparallel side, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Relabeling all four sides of this trapezoid, you can figure how it is composed of a rectangle and two congruent right triangles. You want the HEIGHT of this entire figure. Continue analyzing this figure: the triangles each have 5 yard leg at the bottom, hypotenuse of 13, and unknown other leg, y. \n" ); document.write( "We want this y, because this is the height of the figure: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AREA------- \n" ); document.write( "(Average of the two bases) multiplied by (Altitude of the trapezoid) \n" ); document.write( "Area, \n" ); document.write( "- \n" ); document.write( "13*12=156 square yards \n" ); document.write( " \n" ); document.write( " |