document.write( "Question 71096: \"3 Pipes of different sizes are filling up a pool. Pipe1 fills it up a third of the time that it takes Pipe3, and Pipe2 fills it up a half of the time that it takes Pipe3. How long will it take each pipe to fill up the pool by itself?\"\r
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document.write( " -if you set up a table, i'm not sure where the variable would go, or when you set up the equation[[Pipe 1 work done + Pipe 2 work done + Pipe 3 work done = ?]] should that ? be a 1, for one hour, or a 3, for the 3 hours it took to fill up the pool with all of the pipes? \n" );
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Algebra.Com's Answer #50836 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! \"3 Pipes of different sizes are filling up a pool. Pipe 1 fills it up a third of the time that it takes Pipe 3, and Pipe 2 fills it up a half of the time that it takes Pipe3. How long will it take each pipe to fill up the pool by itself?\" \n" ); document.write( "---------- \n" ); document.write( "Let time for Pipe 3 be 6x hrs/job ; Rate = 1/6x job/hr \n" ); document.write( "Pipe 2 time is 3x hrs/job ; Rate = 1/3x job/hr \n" ); document.write( "Pipe 1 time is 2x hrs/job ; Rate = 1/2x job/hr \n" ); document.write( "Time for all to fill = 3 hrs/job ; Rate = 1/3 job/hr\r \n" ); document.write( "\n" ); document.write( "--------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "rate + rate + rate = rate together \n" ); document.write( "1/6x + 1/3x + 1/2x = 1/3 \n" ); document.write( "Multiply thru by 6x to get: \n" ); document.write( "1 + 2 + 3 = 2x \n" ); document.write( "x=3 hrs. \n" ); document.write( "------------------ \n" ); document.write( "Pipe 3 takes 6x or 18 hrs alone \n" ); document.write( "Pipe 2 takes 3x or 9 hrs. alone \n" ); document.write( "Pipe 1 takes 2x or 6 hrs. alone \n" ); document.write( "----------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |