document.write( "Question 843686: the length of a rectangle is 4 less than twice its width. the area is 70 square inches. find the dimensions of the rectangle
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #508304 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi, Previously Posted
\n" ); document.write( "
\n" ); document.write( "the length of a rectangle is 4 less than twice its width \"+highlight_green%0D%0A%28x%29+\"
\n" ); document.write( "A = \"l%2Aw%29\" = (2x-4)x = 70 in^2
\n" ); document.write( " 2x^2 - 4x - 70 = 0
\n" ); document.write( " (2x+ 10)(x -7 ) = 0 x = 7 (Tossing out the negative solution for unit measure)
\n" ); document.write( " width is 7in and length is 10in \n" ); document.write( "
\n" );