document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71108>Question 71108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one angle of a triangle exceeds another by 23*(degrees). The third is 6*(degrees) less than the sum of the others. FInd the measure of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50829 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+(X+23)+(X+X+23-6)=180<BR>\n" );
document.write( "X+X+23+X+X+23-6=180<BR>\n" );
document.write( "4X=180-46+6<BR>\n" );
document.write( "4X=140<BR>\n" );
document.write( "X=140/4<BR>\n" );
document.write( "X=35 DEGREES IS THE SMALLER ANGLE<BR>\n" );
document.write( "35+23=58 FOR THE MIDDLE ANGLE &<BR>\n" );
document.write( "35+58-6=87 FOR THE LARGER ANGLE<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "35+(35+23)+(35+35+23-6)=180<BR>\n" );
document.write( "35+58+87=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );