document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71082>Question 71082</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0078603900/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\">             write the slope intercept form for an equation of the line parallel to the graph of the given equation and passing through the given point?\r<BR>\n" );
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document.write( "                   3x+9y=1, (3,0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50828 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST WE FIND THE SLOPE OF THE LINE<BR>\n" );
document.write( "3X+9Y+1<BR>\n" );
document.write( "9Y=-3X+1<BR>\n" );
document.write( "Y=-3X/9+1/9<BR>\n" );
document.write( "Y=-X/3+1/9 THIS LINE HAS A SLOPE OF -1/3 SO ANY LINE PARALLEL TO THIS LINE ALSO HAS A SLOPE OF -1/3.<BR>\n" );
document.write( "NOW WE SUBSTITUTE THE (X,Y) VALUES OF THE POINT THAT THE NEW LINE PASSES THROUH & SOLVE FOR THE Y INTERCEPT (b)<BR>\n" );
document.write( "0=3*-1/3+b<BR>\n" );
document.write( "0=-1+b<BR>\n" );
document.write( "b=1 THEREFORE THE LINE FORMULA FOR THIS LINE THROUGH (3,0) WITH A SLOPE OF -1/3 IS<BR>\n" );
document.write( "Y=-X/3+1<BR>\n" );
document.write( "  <BR>\n" );
document.write( " </SPAN>\n" );
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