document.write( "Question 71083This question is from textbook
\n" ); document.write( ": write the slope intercept form for an equation of the line parallel to the graph of the given equation and passing through the given point?\r
\n" ); document.write( "\n" ); document.write( " 3x+9y=1, (3,0)
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Algebra.Com's Answer #50823 by checkley75(3666)\"\" \"About 
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3x+9y=1
\n" ); document.write( "9y=-3x+1
\n" ); document.write( "y=-3x/9+1/9
\n" ); document.write( "y=-x/3+1/9 this line has a slope of -1/3.
\n" ); document.write( "so a parrallel line through (3,0) has the same slope .
\n" ); document.write( "now we substitute the (3,0) values for the x & y values in the line formula & solve for the y intercept(b)
\n" ); document.write( "0=-1/3*3+b
\n" ); document.write( "0=-1+b
\n" ); document.write( "b=1 so this line equation is
\n" ); document.write( "y=-x/3+1
\n" ); document.write( "the graph of these two lines is:
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-x%2F3%2B1%2F9%2C+y+=+-x%2F3+%2B1%29+\" (graph 300x300 pixels, x from -6 to 5, y from -10 to 10, of TWO functions y = -x/3+1/9 and y = -x/3 +1).
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