document.write( "Question 71084This question is from textbook
\n" ); document.write( ": write the slope intercept form for an equation of the line perpendicular to the graph of the given equation and passing through the given point?
\n" ); document.write( " 2x-7y=1, (-4,0)
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Algebra.Com's Answer #50822 by checkley75(3666)\"\" \"About 
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2x-7y=1
\n" ); document.write( "-7y=-2x+1
\n" ); document.write( "y=-2x/-7+1/-7
\n" ); document.write( "y=2x/7-1/7 the given line has a slope of 2/7.
\n" ); document.write( "therefore the perpendicular lines slope is the negative reciprical (-7/2)
\n" ); document.write( "now replace the x & y values in the line equation y=mx+b with (-4,0) & sole for the y intercept (b)
\n" ); document.write( "0=-7/2*-4+b
\n" ); document.write( "0=28/2+b
\n" ); document.write( "b=-28/2
\n" ); document.write( "b=-14 thus the equation of the perpendicular line is
\n" ); document.write( "y=-7x/2-14
\n" ); document.write( "here are the two libnes plotted\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+y+=+2x%2F7+-1%2F7%2C+y+=+-7x%2F2+-14%29+\" (graph 300x200 pixels, x from -5 to 5, y from -5 to 5, of TWO functions y = 2x/7 -1/7 and y = -7x/2 -14).
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