document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=843510>Question 843510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An engineer undertakes a project to build a road of 15 km long in 300 days and employs 45 men for the purpose.after 100 days he finds only 2.5 km of the road has been completed.find the number of extra men he must employ to finish the work in time.with process. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #508153 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=508153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 45*100=4500 man days for 2.5 km<BR>\n" );
document.write( "The road will take 15/2.5=6  times 100=600 total days  to finish or 500 more days<BR>\n" );
document.write( "There is already 2.5 finished so for 12.5 km  12.5/2.5=5<BR>\n" );
document.write( "so he needs 4500*5 man days.  22500 man days/200 =112.5 men to finish the job in 200 more days.<BR>\n" );
document.write( "We can't just hire a half a man so we will need 113 men total 113-45=68 more men.\r<BR>\n" );
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