document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71093>Question 71093</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50814 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the two numbers are x & (x+1)<BR>\n" );
document.write( "2x+4(x+1)=46<BR>\n" );
document.write( "2x+4x+4=46<BR>\n" );
document.write( "6x=46-4<BR>\n" );
document.write( "6x=42<BR>\n" );
document.write( "x=42/6<BR>\n" );
document.write( "x=7 answer for the first number &<BR>\n" );
document.write( "7+1=8 for the second number <BR>\n" );
document.write( "proof<BR>\n" );
document.write( "2*7+4*8=46<BR>\n" );
document.write( "14+32=46<BR>\n" );
document.write( "46=46<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );