document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=843419>Question 843419</A>: <I><SPAN STYLE=\"word-break: break-all;\">  How do you solve this for a system equation y= -x     y= 2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #508095 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=508095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first equation tells you that y = -x.  Substitute -x for y in the second equation.<P><BR>\n" );
document.write( "-x = 2x : add x to both sides<P><BR>\n" );
document.write( "0 = 2x + x = 3x : Divide both sides by 3.<P><BR>\n" );
document.write( "0=x :  Substitute 0 for x in the first equation.<P><BR>\n" );
document.write( "y = -0 = 0<P><BR>\n" );
document.write( "Both x and y = 0. </SPAN>\n" );
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