document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=843378>Question 843378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose you had 140 feet of fence to make a rectangular garden. What are possible dimensions of the garden? What length and width would give you the maximum area?\r<BR>\n" );
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document.write( "I know you use the 2L+2W=140<BR>\n" );
document.write( "                    L+W=70, but how do I find the length and width that would give me the maximum area?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #508087 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=508087\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The maximum area occurs when the rectangular garden is a square of side length 35 ft. To prove this, note that A = LW = L(70-L), the vertex of the parabola occurs at L = 35 ft. Can also be proven via AM-GM inequality or calculus. </SPAN>\n" );
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