document.write( "Question 843032: Please help me solve: Erica deposited a total of $6,000 into two simple interest accounts. On one account the interest rate is 4.4%, on the second account the interest rate is 3%/ How much should Sarah invest in each account so that the 3% account ears $65 more in interest than the 4.4% account? Round your answers to the nearest cent.
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Algebra.Com's Answer #508070 by ankor@dixie-net.com(22740)\"\" \"About 
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let a = amt invested at 4.4%
\n" ); document.write( "let b = amt invested at 3%
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "Erica deposited a total of $6,000 into two simple interest accounts.
\n" ); document.write( "a + b = 6000
\n" ); document.write( "a = (6000-b)
\n" ); document.write( " On one account the interest rate is 4.4%, on the second account the interest rate is 3%/
\n" ); document.write( "How much should Sarah invest in each account so that the 3% account ears $65 more in interest than the 4.4% account?
\n" ); document.write( ".03b - .044a = 65
\n" ); document.write( "Replace a with (6000-b)
\n" ); document.write( ".03b - .044(6000-b) = 65
\n" ); document.write( ".03b - 264 + .044b = 65
\n" ); document.write( ".03b + .044b = 65 + 264
\n" ); document.write( ".074b = 329
\n" ); document.write( "b = 329/.074
\n" ); document.write( "b = $4445.95 invested at 3%
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\n" ); document.write( "I'll let you find the amt invested at 4.4%, see the difference is = 65 \n" ); document.write( "
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