document.write( "Question 843241: Find the associated exponential decay or growth model.
\n" ); document.write( "Q = 1,800 when t = 0; half-life = 5
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Algebra.Com's Answer #508029 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
Solve this generally for k: \"A=Qe%5E%28-kt%29\";\r
\n" ); document.write( "\n" ); document.write( "Let t=5, A=(1/2)Q, , and find the formula this way for k.\r
\n" ); document.write( "\n" ); document.write( "Rewrite \"A=1800e%5E%28-k%2At%29\" using the value you found for k.\r
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\n" ); document.write( "\n" ); document.write( "Best if you follow that and do it.
\n" ); document.write( "I did not show you the specific steps. Do you need them?\r
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\n" ); document.write( "\n" ); document.write( "SOLUTION WITH NEARLY ALL STEPS SHOWN--------------------------------\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28A=Qe%5E%28-kt%29%29\"------Basic Model for Decay
\n" ); document.write( "\"ln%28A%29=ln%28Q%29%2Bln%28e%5E%28-kt%29%29\"
\n" ); document.write( "\"ln%28A%29-ln%28Q%29=-kt%2A1\"
\n" ); document.write( "\"highlight_green%28k=%28ln%28Q%29-ln%28A%29%29%2Ft%29\"\r
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\n" ); document.write( "\n" ); document.write( "The specific example has initial half life of 5 years, t=5 with \"A=Q%2F2\", enough for finding the value of k.
\n" ); document.write( "\"k=ln%28Q%2FA%29%2Ft\"
\n" ); document.write( "\"k=ln%28Q%2F%28Q%2F2%29%29%2F5\"
\n" ); document.write( "\"highlight_green%28k=ln%282%29%2F5%29\"
\n" ); document.write( "But as a decimal number, this can be stated \"highlight%28k=0.1386%29\"\r
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\n" ); document.write( "\n" ); document.write( "The specific model equation based on given Q=1800 and the found value for k, becomes \"highlight%28highlight%28A=1800%2Ae%5E%28-0.1386%2At%29%29%29\"
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