document.write( "Question 843189: If the length of a rectangle is 11 2/3 inches and the width is 4 2/7 inch, find the area of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "please help, I tried multiplying 11*3+2=35 and 4*7+2=30 but I did not get the answer of 50in^2... Please help\r
\n" ); document.write( "\n" ); document.write( "Thank you \n" ); document.write( "
Algebra.Com's Answer #507983 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
length is equal to 11 2/3 inches.
\n" ); document.write( "width is 4 2/7 inches.
\n" ); document.write( "area is equal to length times width.
\n" ); document.write( "it's easiest to convert the mixed fractions to improper fractions and then do the multiplying.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "11 and 2/3 inches is equal to 35/3 inches.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "4 and 2/7 inches is equal to 30/7 inches.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "you now need to multiply 35/3 * 30/7.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "it looks like you did the conversion correctly but forgot the denominators.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );