document.write( "Question 71085This question is from textbook
\n" ); document.write( ": write the slope intercept form for an equation of the line perpendicular to the graph of the given equation and passing through the given point?
\n" ); document.write( " 5y=-x+1, (2,-5)
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #50797 by checkley75(3666) $\"\"$ $\"About$

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5y=-x+1
\n" ); document.write( "y=-x/5+1/5 thus a line perpendicular to this line has a slope of 5 & passes through(2,-5)
\n" ); document.write( "-5=5*2+b
\n" ); document.write( "-5=10+b
\n" ); document.write( "b=-5-10
\n" ); document.write( "b=-15
\n" ); document.write( "so the equation for this line is
\n" ); document.write( "y=5x-15
\n" ); document.write( "here is the graph of these two lines
\n" ); document.write( " $\"+graph%28+400%2C+400%2C+-16%2C+16%2C+-16%2C+16%2Cy+=+-x%2F5+%2B1%2F5%2C+y+=+5x+-15%29+\"$ (graph 400x400 pixels, x from -16 to 16, y from -16 to 16, of TWO functions y = -x/5 +1/5 and y = 5x -15). \n" ); document.write( "

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