document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71073>Question 71073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many quarts of water does one add to 6 quarts of a 60% alcohol solution to create a 40% alcohol solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50794 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of quarts of water to be added\r<BR>\n" );
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document.write( "The amount of pure alcohol before adding water = amount of pure alcohol after adding water.  So our equation to solve is:\r<BR>\n" );
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document.write( "6(.60)=(6+x)(.40)  clear parens\r<BR>\n" );
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document.write( "3.60=2.40+.4x  subtract 2.40 from both sides\r<BR>\n" );
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document.write( "3.60-2.40=2.40-2.40+.40x<BR>\n" );
document.write( "1.20=.40x<BR>\n" );
document.write( "x=3 qts-------------------------------answer\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "6(.6)=9(.4)\r<BR>\n" );
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document.write( "3.6=3.6\r<BR>\n" );
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document.write( "Hope this helps-----ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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