document.write( "Question 841301: hence,prove algebraically that the sum of any two consecutive terms is a perfect square 3;x;10;y;21 \n" ); document.write( "
Algebra.Com's Answer #507788 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "You start your question with \"hence\", so we cannot be sure\r\n" ); document.write( "what went before that, and how you are supposed to come up\r\n" ); document.write( "with x and y. I observe that the three numbers given 3,10,21 \r\n" ); document.write( "appear in Pascal's triangle \r\n" ); document.write( " \r\n" ); document.write( " 1\r\n" ); document.write( " 1 1\r\n" ); document.write( " 1 2 1\r\n" ); document.write( " 1 3 3 1\r\n" ); document.write( " 1 4 6 4 1\r\n" ); document.write( " 1 5 10 10 5 1\r\n" ); document.write( " 1 6 15 20 15 6 1\r\n" ); document.write( "1 7 21 35 35 21 7 1\r\n" ); document.write( "\r\n" ); document.write( "Pascal's triangle is composed of binomial coefficients which \r\n" ); document.write( "are combinations: \r\n" ); document.write( "\r\n" ); document.write( "3 = C(3,2), 10 = C(5,2), 21 = C(7,2)\r\n" ); document.write( "\r\n" ); document.write( "So I assume that the sequence 3,x,10,y,21 is this sequence:\r\n" ); document.write( "\r\n" ); document.write( "3=C(3,2), x=C(4,2), 10=C(5,2), y=C(6,2), 21=C(7,2) \r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |