document.write( "Question 71018: (3x -sqrt5/3x +sqrt5) \n" ); document.write( "
Algebra.Com's Answer #50776 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(3x -sqrt5/3x +sqrt5)
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\n" ); document.write( "Multiply numerator and denominator by 3x-sqrt5 to get:
\n" ); document.write( "(3x - sqrt5)^2 / [(3x+sqrt5)(3x-sqrt5)]\r
\n" ); document.write( "\n" ); document.write( "= (3x - sqrt5)^2 / (9x^2 - 5)\r
\n" ); document.write( "\n" ); document.write( "= [9x^2 - 6sqrt5 x +5]/ [ 9x^2 - 5]\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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