document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71023>Question 71023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular garden is to be surrounded by a walkway of constant width.  The garden's dimensions are 30 ft by 40 ft.  The total area, garden plus walkway, is to be 1800 ft2.  What must be the width of the walkway to the nearest thousandth? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50775 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> garden=30*40=1200 ft^2<BR>\n" );
document.write( "garden+walkway=1800 ft^2<BR>\n" );
document.write( "let walkway width be x ft. then<BR>\n" );
document.write( "(30+2x)*(40+2x)=1800<BR>\n" );
document.write( "1200+80x+60x+4x^2=1800<BR>\n" );
document.write( "4x^2+140x+1200-1800=0<BR>\n" );
document.write( "4x^2+140x-600=0<BR>\n" );
document.write( "using the quadratic equation we get<BR>\n" );
document.write( "x=(-b+-sqrt[b^2-4ac])/2a<BR>\n" );
document.write( "x=(-140+-sqrt[140^2-4*4*-600])/2*4<BR>\n" );
document.write( "x=(-140+-sqrt[19600+9600)/8<BR>\n" );
document.write( "x=(-140+-sqrt29200])/8<BR>\n" );
document.write( "x=(-140+-170.88)/8<BR>\n" );
document.write( "x=(-140+170.88)/8<BR>\n" );
document.write( "x=30.88/8<BR>\n" );
document.write( "x=3.86 feet for the walkway\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );