document.write( "Question 842692: a newspaper carrier has $3.35 in change. He has seven more quarters than dimes but two times as many nickles as quarters. How many coins of each does he have? \n" ); document.write( "
Algebra.Com's Answer #507707 by LinnW(1048)\"\" \"About 
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set n = no of nickles
\n" ); document.write( " d = no of dimes
\n" ); document.write( " q = no of quarters
\n" ); document.write( "0.05(n) + 0.10(d) + 0.25(q) = 3.35
\n" ); document.write( "q = d + 7
\n" ); document.write( "n = 2q
\n" ); document.write( "So n = 2(d + 7)
\n" ); document.write( "n = 2d + 14
\n" ); document.write( "substitute in 0.05(n) + 0.10(d) + 0.25(q) = 3.35
\n" ); document.write( "0.05(2d + 14) + 0.10(d) + 0.25(d + 7) = 3.35
\n" ); document.write( "0.10d + 0.70 + 0.10d + 0.25d + 1.75 = 3.35
\n" ); document.write( "0.45d + 2.45 = 3.35
\n" ); document.write( "add -2.45 to each side
\n" ); document.write( "0.45d = 0.90
\n" ); document.write( "d = 2
\n" ); document.write( "since q = d + 7, q = 2 + 7 = 9
\n" ); document.write( "since q = 9 and n = 2q , n = 2(9) = 18
\n" ); document.write( "checking
\n" ); document.write( "0.05(18) + 0.10(2) + 0.25(9) =? 3.35
\n" ); document.write( "0.90 + 0.20 + 2.25 =? 3.35
\n" ); document.write( "3.35 = 3.35
\n" ); document.write( "so n = 18, d = 2, and q = 9
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