document.write( "Question 842649: let g and h be two functions defined by: \r
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document.write( " g(x)=(x-1)(x-6)
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document.write( " h(x)=-9x+1 \r
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document.write( " for any real number x. \r
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document.write( "Find g/h(2) and then find all values that are NOT in the domain of g/h. If there is more than one value, separate them with commas.\r
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document.write( "so I have g/h(2):\r
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document.write( "(x-1)(x-6)/-9x+1(2)
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document.write( "I don't know how to find the values that are NOT in the domain of g/h. \n" );
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Algebra.Com's Answer #507691 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! h(2)=-9*2+1 \n" ); document.write( "h(2)=-17\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "The domain for this is all real numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The domain for \n" ); document.write( " \n" ); document.write( "Values of x NOT in the domain of g/h is only one value. \n" ); document.write( "The ratio g/h cannot accept \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |