document.write( "Question 842649: let g and h be two functions defined by: \r
\n" ); document.write( "\n" ); document.write( " g(x)=(x-1)(x-6)
\n" ); document.write( " h(x)=-9x+1 \r
\n" ); document.write( "\n" ); document.write( " for any real number x. \r
\n" ); document.write( "\n" ); document.write( "Find g/h(2) and then find all values that are NOT in the domain of g/h. If there is more than one value, separate them with commas.\r
\n" ); document.write( "\n" ); document.write( "so I have g/h(2):\r
\n" ); document.write( "\n" ); document.write( "(x-1)(x-6)/-9x+1(2)
\n" ); document.write( "I don't know how to find the values that are NOT in the domain of g/h.
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Algebra.Com's Answer #507691 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
h(2)=-9*2+1
\n" ); document.write( "h(2)=-17\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"g%2Fh%282%29=%28x-1%29%28x-6%29%2Fh%282%29=-%28x-1%29%28x-6%29%2F17\".
\n" ); document.write( "The domain for this is all real numbers.\r
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\n" ); document.write( "\n" ); document.write( "The domain for \"g%28x%29%2Fh%28x%29\"?
\n" ); document.write( "\"%28x-1%29%28x-6%29%2F%28-9x%2B1%29\".
\n" ); document.write( "Values of x NOT in the domain of g/h is only one value.
\n" ); document.write( "The ratio g/h cannot accept \"-9x%2B1=0\"
\n" ); document.write( "\"-9x=-1\"
\n" ); document.write( "\"9x=1\"
\n" ); document.write( "\"highlight%28x=1%2F9%29\"-------This is the value of x NOT in the domain of \"g%28x%29%2F%28h%28x%29%29\".
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