document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=842620>Question 842620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A picture frame has a perimeter of 100 cm. Its width is 4 cm less than twice its length. What is the width of the picture frame? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #507666 by </B><A HREF=/tutors/aboutme.mpl?userid=thejackal><B>thejackal(72)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thejackal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thejackal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=507666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter P = 2w + 2l where w is width and l is length\r<BR>\n" );
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document.write( "if w = 2l - 4 as said in the question then\r<BR>\n" );
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document.write( "P = 2(2l - 4) + 2l<BR>\n" );
document.write( "P = 4l - 8 + 2l<BR>\n" );
document.write( "P = 6l - 8\r<BR>\n" );
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document.write( "thus\r<BR>\n" );
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document.write( "100 = 6l - 8<BR>\n" );
document.write( "100 + 8 = 6l<BR>\n" );
document.write( "108 = 6l<BR>\n" );
document.write( "108/6 = l = 18\r<BR>\n" );
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document.write( "thus w = 2(18) - 4 = 36 - 4 = 32\r<BR>\n" );
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document.write( " </SPAN>\n" );
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