document.write( "Question 842617: Solve for X and Y :\r
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document.write( "8/x + 6/y = 6 and 1/x + 1/y = 1/6 \n" );
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Algebra.Com's Answer #507659 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! 8/x + 6/y = 6 and 1/x + 1/y = 1/6 \n" ); document.write( "8/x + 6/y = 6 and 1/x + 1/y = 1/6 \n" ); document.write( "multiply the second equation by 36 \n" ); document.write( "36( 1/x + 1/y = 1/6 ) = 36/x + 36/y = 6 \n" ); document.write( "Since 8/x + 6/y = 6 \n" ); document.write( "8/x + 6/y = 36/x + 36/y \n" ); document.write( "add -8/x -6/y to each side \n" ); document.write( "0 = 28/x + 30/y \n" ); document.write( "add -30/y to each side \n" ); document.write( " \n" ); document.write( "do cross products \n" ); document.write( "28y = -30x \n" ); document.write( "divide by 28 \n" ); document.write( "y = \n" ); document.write( "substitute \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "do cross products \n" ); document.write( "30x=12 \n" ); document.write( "divide each side by 30 \n" ); document.write( "x = 12/30 = 2/5 \n" ); document.write( "We previously determined that y = \n" ); document.write( "so substituting 2/5 for x we have \n" ); document.write( "y = \n" ); document.write( "y = \n" ); document.write( "summarizing x = 2/5 , y = -3/7 \n" ); document.write( " |