document.write( "Question 842595: 40 biscuits are shared amongst three children,A,B and C ,so that B has four more than A and C has twice as many as B.how many do they each have \n" ); document.write( "

Algebra.Com's Answer #507648 by thejackal(72) $\"\"$ $\"About$

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formulate an equation out of the description.
\n" ); document.write( "What do we know:
\n" ); document.write( "1) there are 40 biscuits
\n" ); document.write( "2) there are 3 children
\n" ); document.write( "3) B has four more than A which said another way whatever A has, B has 4 + A's
\n" ); document.write( "4) C has twice as many as B's which is the same as saying 2 * (4 + A's)\r
\n" ); document.write( "\n" ); document.write( "when we put all this together we have a simple equation with only one unknown. lets call A's number of biscuits x to be clearer so that\r
\n" ); document.write( "\n" ); document.write( "x + (4+x) + 2(4+x) = 40; this is saying A's biscuits + B's biscuits + C's biscuits = 40\r
\n" ); document.write( "\n" ); document.write( "solve for x by simplifying first\r
\n" ); document.write( "\n" ); document.write( "2x + 4 + 8 + 2x = 40
\n" ); document.write( "4x + 12 = 40
\n" ); document.write( "4x = 40 - 12 = 28
\n" ); document.write( "x = 7 = A's biscuits\r
\n" ); document.write( "\n" ); document.write( "go back to equation 3 so that B's biscuits = 7 + 4 = 11
\n" ); document.write( "go back to equation 4 so that C's biscuits = 11 * 2 = 22\r
\n" ); document.write( "\n" ); document.write( "check your answer is 11+22+7 = 40?\r
\n" ); document.write( "\n" ); document.write( "Q.E.D \n" ); document.write( "

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