document.write( "Question 842595: 40 biscuits are shared amongst three children,A,B and C ,so that B has four more than A and C has twice as many as B.how many do they each have \n" ); document.write( "

Algebra.Com's Answer #507645 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "A     7
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document.write( "B     11
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document.write( "C  22
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document.write( " A+ B + C=  40
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document.write( "  4x + 12 = 40
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document.write( "     4x = 28
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document.write( "      x = 7 
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document.write( "CHECKING our answer***
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document.write( "  7 + 11 + 22 = 40
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document.write( "Wish You the Best in your Studies.
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