document.write( "Question 842555: A truck driver traveled at an average speed of 55mph on a 200 mile trip to pick up a load of freight . On the return trip (with the truck fully loaded), the average speed was 40 miles per hour. What was the average speed for the round trip ? \n" ); document.write( "

Algebra.Com's Answer #507643 by josmiceli(19441) $\"\"$ $\"About$

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Average speed is always ( total distance traveled ) / ( total time for travel )
\n" ); document.write( " $\"+d+=+r%2At+\"$
\n" ); document.write( " $\"+200+=+55t%5B1%5D+\"$
\n" ); document.write( " $\"+t%5B1%5D+=+40%2F11+\"$ hrs
\n" ); document.write( "and, for the return trip:
\n" ); document.write( " $\"+200+=+40t%5B2%5D+\"$
\n" ); document.write( " $\"+t%5B2%5D+=+5+\"$ hrs
\n" ); document.write( "------------------
\n" ); document.write( "The total distance is $\"+2%2A200+=+400+\"$
\n" ); document.write( "The total time is: $\"+40%2F11+%2B+55%2F11+=+95%2F11+\"$
\n" ); document.write( " $\"+95%2F11+=+8.6364+\"$
\n" ); document.write( "Average speed = $\"+400%2F8.6364+\"$
\n" ); document.write( " $\"+400%2F8.6364+=+46.316+\"$ mi/hr
\n" ); document.write( " \n" ); document.write( "

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