document.write( "Question 842552: Eighty percent of (80%)of business travelers carry either a cell phone or a laptop. Assume a binomial probability distribution for the number x of business travelers carrying a cell phone or a laptop om a given sample.
\n" ); document.write( "Suppose that a sample of 15 business travelers is randomly selected.\r
\n" ); document.write( "\n" ); document.write( "A)what are the possible values of the number of business travelers carrying a cell phone or a laptop in the sample? x=\r
\n" ); document.write( "\n" ); document.write( "B)What is the expected number of business travelers carrying a phone or a laptop in such a sample?\r
\n" ); document.write( "\n" ); document.write( "C) Is this probability distribution skewed to right or left?\r
\n" ); document.write( "\n" ); document.write( "D)Compute the standard deviation of the number of business travelers carrying a phone or a laptop in such a sample.\r
\n" ); document.write( "\n" ); document.write( "E)What is the probability that exactly 8 business travelers in a sample carry a cell phone or a laptop?\r
\n" ); document.write( "\n" ); document.write( "F)What is the probability that 7 of the 15 business travelers have neither a cell phone nor a laptop?\r
\n" ); document.write( "\n" ); document.write( "G)What is the probability that at least 10(ten) business travelers in the sample have a cell phone or a laptop?\r
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\n" ); document.write( "\n" ); document.write( "I'm having trouble with this problem \r
\n" ); document.write( "\n" ); document.write( "thank you in advance for your help :)\r
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Algebra.Com's Answer #507623 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "Note: The probability of x successes in n trials is:
\n" ); document.write( "P = nCx* \"p%5Ex%2Aq%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p(carry either a cell phone or a laptop) = .8 & q = .2 and n = 15
\n" ); document.write( "A)what are the possible values of the number of business travelers carrying a cell phone or a laptop in the sample?
\n" ); document.write( " 0 ≤ x ≤ 15
\n" ); document.write( "B)What is the expected number of business travelers carrying a phone or a laptop in such a sample? \".8%2A15+=+12\"
\n" ); document.write( "C) Is this probability distribution skewed to right or left?
\n" ); document.write( "Note: distributions with fewer observations on the left (toward lower values) are said to be skewed left.
\n" ); document.write( "D)Compute the standard deviation of the number of business travelers carrying a phone or a laptop in such a sample. \"sqrt%2815%2A.8%2A.2%29\"
\n" ); document.write( "E)What is the probability that exactly 8 business travelers in a sample carry a cell phone or a laptop?
\n" ); document.write( "TI Calculator: binompdf(n, p, x-value) = binompdf(15, .8,8)
\n" ); document.write( "F)What is the probability that 7 of the 15 business travelers have neither a cell phone nor a laptop? binompdf(15, .2,7)
\n" ); document.write( "G)What is the probability that at least 10(ten) business travelers in the sample have a cell phone or a laptop?
\n" ); document.write( "1 – binomcdf(n, p, largest x-value)= 1 – binomcdf(15, .8, 9) \n" ); document.write( "
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