document.write( "Question 842506: Sally is Bob's younger sister, and she is 7 years younger than Bob. If you multiply Bob's age by three, and subtract sally's age, you get their mother's age, which is 37. How old is Sally? \n" ); document.write( "
Algebra.Com's Answer #507592 by TheInstructor(29)![]() ![]() ![]() You can put this solution on YOUR website! Let Bob = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sally = x-7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply Bob's age by 3: 3x \n" ); document.write( "Subtract Sally's age: 3x-(x-7) = 2x+7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+7 = 37 \n" ); document.write( "Therefore x= 15\r \n" ); document.write( "\n" ); document.write( "Bob = 15 \n" ); document.write( "Sally = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope that helped! Feel free to leave a message for any inquiries! =] \n" ); document.write( " |