document.write( "Question 71027: Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end of the year is $490, how much did he invest at 8%?\r
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Algebra.Com's Answer #50759 by checkley75(3666)\"\" \"About 
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.08x+.17(5000-x)=490
\n" ); document.write( ".08x+850-.17x=490
\n" ); document.write( "-.09x=490-850
\n" ); document.write( "-.09x=-360
\n" ); document.write( "x=-360/-.09
\n" ); document.write( "x=4000 invested @ 8%
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\n" ); document.write( ".08*4000+.17(5000-4000)=490
\n" ); document.write( "320+.17(1000)=490
\n" ); document.write( "320+170=490
\n" ); document.write( "490=490
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