document.write( "Question 71027: Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end of the year is $490, how much did he invest at 8%?\r
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Algebra.Com's Answer #50759 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .08x+.17(5000-x)=490 \n" ); document.write( ".08x+850-.17x=490 \n" ); document.write( "-.09x=490-850 \n" ); document.write( "-.09x=-360 \n" ); document.write( "x=-360/-.09 \n" ); document.write( "x=4000 invested @ 8% \n" ); document.write( "proof \n" ); document.write( ".08*4000+.17(5000-4000)=490 \n" ); document.write( "320+.17(1000)=490 \n" ); document.write( "320+170=490 \n" ); document.write( "490=490 \n" ); document.write( " \n" ); document.write( " |