document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71028>Question 71028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system by graphing.<BR>\n" );
document.write( "	3x – y = 1<BR>\n" );
document.write( "	3x – y = 2<BR>\n" );
document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50758 by </B><A HREF=/tutors/aboutme.mpl?userid=Alg_Whiz_Kid><B>Alg_Whiz_Kid(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alg_Whiz_Kid><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x – y = 1<BR>\n" );
document.write( "3x – y = 2\r<BR>\n" );
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document.write( "Okay, here's how you do it. I used the slope formula, y = mx + b. First you need to get y by itself, that way you can graph. So for the first one, 3x - y = 1, you're going to move the x over to the right, making it -y = -3x + 1. You need the y to be positve, so divide by a negative, or change the signs of everything. Now you have y = 3x - 1. The y intercept is -1 so put a point at (0,-1). Then you can use a T-Table or the slope. I use the slope because it's easier, so here is how you can do it with the slope:<BR>\n" );
document.write( "Change the 3 to 3/1, that way you know the rise and the run, so from the point (0,-1), go up 3 and right 1, and then do it again and make your line! </SPAN>\n" );
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