document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=842441>Question 842441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please Help!\r<BR>\n" );
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document.write( "The sum of the reciprocal of two positive numbers is 1/9, and one of the numbers is 3 times the other. find the numbers  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #507577 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=507577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = one of the numbers.<BR>\n" );
document.write( "let 3x = the other number.<BR>\n" );
document.write( "the reciprocal of x is equal to 1/x.<BR>\n" );
document.write( "the reciprocal of 3x is equal to 1/3x<BR>\n" );
document.write( "the sum of the reciprocals of the number is equal to 1/9.<BR>\n" );
document.write( "your equation is:<BR>\n" );
document.write( "1/x + 1/3x = 1/9<BR>\n" );
document.write( "multiply both sides of this equation by 3x to get:<BR>\n" );
document.write( "3 + 1 = 3x/9<BR>\n" );
document.write( "simplify to get 4 = 3x/9<BR>\n" );
document.write( "multiply both sides of this equation by 9 to get:<BR>\n" );
document.write( "36 = 3x<BR>\n" );
document.write( "divide both sides of this equation by 3 to get:<BR>\n" );
document.write( "12 = x<BR>\n" );
document.write( "that should be your answer.<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "one of the number is equal to 12.<BR>\n" );
document.write( "the other number is equal to 3*12 - 36.<BR>\n" );
document.write( "the sum of the reciprocals of these number should be equal to 1/9.<BR>\n" );
document.write( "the reciprocal of 12 is 1/12.<BR>\n" );
document.write( "the reciprocal of 36 is 1/36.<BR>\n" );
document.write( "you get:<BR>\n" );
document.write( "1/12 + 1/36 = 1/9<BR>\n" );
document.write( "a common denominator would be equal to 36 since 12 goes into 36<BR>\n" );
document.write( "converting the left side of the equation to common denominators, your equation becomes:<BR>\n" );
document.write( "3/36 + 1/36 = 1/9<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "4/36 = 1/9<BR>\n" );
document.write( "if you multiply the right side of the equation by 4/4, you get:<BR>\n" );
document.write( "4/36 = 4/36 which is true, confirming that the value of x = 12 is good.<BR>\n" );
document.write( "your numbers are 12 and 36.\r<BR>\n" );
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