document.write( "Question 842476: A baker packed 32 doughnuts into 3 boxes. She put a different number of doughnuts into each box and there was an even amount in each box.
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Algebra.Com's Answer #507562 by josgarithmetic(39618)\"\" \"About 
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\"32%2F2=16\";
\n" ); document.write( "\"32%2F3=10%262%2F3\";
\n" ); document.write( "\"32%2F4=8\".\r
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\n" ); document.write( "\n" ); document.write( "Three boxes must distribute these 32 doughnuts. .
\n" ); document.write( "Start with 10 and 12. That would be 22 doughnuts. Another with 8 will finish the 32. That is about the best way to distribute these 32 doughnuts.
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\n" ); document.write( "Boxes each for 8, 10, 12 doughnuts\r
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\n" ); document.write( "\n" ); document.write( "ANOTHER TRY
\n" ); document.write( "16+12=28, and then third box to contain 4.
\n" ); document.write( "This is not as neat as the first described combination.\r
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\n" ); document.write( "\n" ); document.write( "ANOTHER
\n" ); document.write( "14+12=26 and then third box to contain 6.
\n" ); document.write( "Still not as uniform as the first described combination.
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