document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=842353>Question 842353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I solved the diameter using C=2pir I got C=2(3.14)(3)=18.84 (I was wrong)\r<BR>\n" );
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document.write( "How many square feet of concrete surface are there in a circular walkway 8ft wide surrounding a tree if the tree has a diameter of 3ft. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #507531 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=507531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the center of the tree to the inner edge of the walk is 3 feet. <BR>\n" );
document.write( "From the center of the tree to the outer edge of the walk is (3+8) 11 feet.<BR>\n" );
document.write( "The area of cement is the area of a circle with radius of 11 feet minus the area of a circle with a radius of 3 ft.<BR>\n" );
document.write( "The area of a circle is,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bcircle%5D=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"A%5Bcircle%5D=pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The area of the cement is then,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bcement%5D=pi%2811%5E2-3%5E2%29=pi%2A%28121-9%29=112%2Api ALIGN=MIDDLE  ALT=\"A%5Bcement%5D=pi%2811%5E2-3%5E2%29=pi%2A%28121-9%29=112%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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