document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=842378>Question 842378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three consecutive integers is 468. find the numbers by writing and solving an equation... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #507525 by </B><A HREF=/tutors/aboutme.mpl?userid=Narsinghchauhan8960103366><B>Narsinghchauhan8960103366(17)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Narsinghchauhan8960103366><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Narsinghchauhan8960103366><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=507525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first no = x<BR>\n" );
document.write( "So second no = (x+1)<BR>\n" );
document.write( "And third no = x+1+1<BR>\n" );
document.write( "=(x+2)<BR>\n" );
document.write( "According to question<BR>\n" );
document.write( "x+(x+1)+(x+2)=468<BR>\n" );
document.write( "3x+3=468<BR>\n" );
document.write( "3x=468-3=465<BR>\n" );
document.write( "x=465/3=155<BR>\n" );
document.write( "first no = x=155<BR>\n" );
document.write( "So second no = (x+1)=155+1=156<BR>\n" );
document.write( "And third no =(x+2)=155+2=157 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );