document.write( "Question 842202: The perimeter of a playground is 504 and 2/3 yards. The length is 6 yards shorter than twice the width. What is the area of the playground? \n" ); document.write( "

Algebra.Com's Answer #507433 by LinnW(1048) $\"\"$ $\"About$

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set L = length
\n" ); document.write( " W = width
\n" ); document.write( "L = 2W -6
\n" ); document.write( "L*W = 504 2/3
\n" ); document.write( "L*W = 1514/3
\n" ); document.write( "substitute 2W -6 for L
\n" ); document.write( "(2W -6)(W) = 1514/3
\n" ); document.write( "2W^2 -6W = 1514/3
\n" ); document.write( "add - 1514/3 to each side
\n" ); document.write( "2W^2 -6W - 1514/3 = 0
\n" ); document.write( "multiply by 3
\n" ); document.write( "6W^2 -18W -1514 = 0
\n" ); document.write( "W = (1/6)*(9+sqrt(9165))
\n" ); document.write( "W = (1/6)*(9-sqrt(9165)) , but this number is negative so does not work.\r
\n" ); document.write( "\n" ); document.write( "L = $\"2%28%281%2F6%29%2A%289%2Bsqrt%289165%29%29%29+-+6\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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