document.write( "Question 71010: Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin does she have? \n" ); document.write( "
Algebra.Com's Answer #50743 by piglet162431(90)\"\" \"About 
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soo
\n" ); document.write( "let statements:
\n" ); document.write( "let x be the number of nickels
\n" ); document.write( "let y be the number of dimes
\n" ); document.write( "since there are 50 coins, we can say
\n" ); document.write( "x+y=50
\n" ); document.write( "since in total the value of these coins are $3.50
\n" ); document.write( ".05x+.1y=3.50
\n" ); document.write( "to make things simply, why not times the equation by 100
\n" ); document.write( "5x+10y=350
\n" ); document.write( "Now use substitution method.
\n" ); document.write( "from the 1st equation, y=50-x
\n" ); document.write( "5x+10(50-x)=350
\n" ); document.write( "5x+500-10x=350
\n" ); document.write( "-5x=-150
\n" ); document.write( "x=30
\n" ); document.write( "y=20
\n" ); document.write( "There are 30 nickels and 20 dimes.\r
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