document.write( "Question 842035: Two cars leave towns
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document.write( "760
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document.write( " kilometers apart at the same time and travel toward each other. One car's rate is
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document.write( "16
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document.write( " kilometers per hour less than the other's. If they meet in
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document.write( "4
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document.write( " hours, what is the rate of the slower car?
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document.write( "Do not do any rounding. \n" );
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Algebra.Com's Answer #507348 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! r = rate of slower car. \n" ); document.write( "R*T=D for Rate, Time, Distance\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "________________speed____________time_____________distance \n" ); document.write( "Fast____________r+16______________4_______________ \n" ); document.write( "Slow_____________r________________4________________ \n" ); document.write( "Total______________________________________________760\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation to formulate should appear obvious. \n" ); document.write( " |