document.write( "Question 70988: Please help me solve: 3x-2 over 4x = 3 over x + 1 over 2 \n" ); document.write( "
Algebra.Com's Answer #50731 by Earlsdon(6294)\"\" \"About 
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\n" ); document.write( "\"%283x-2%29%2F4x+=+3%2Fx+%2B+1%2F2\" Is this it? If so, let's proceed. Add the fractions on the right side.
\n" ); document.write( "\"%283x-2%29%2F4x+=+12%2F4x+%2B+2x%2F4x\" Simplify.
\n" ); document.write( "\"%283x-2%29%2F4x+=+%2812%2B2x%29%2F4x\" so:
\n" ); document.write( "\"3x-2+=+12%2B2x\" Subtract 2x from both sides.
\n" ); document.write( "\"x-2+=+12\" Add 2 to both sides.
\n" ); document.write( "\"x+=+14\"
\n" ); document.write( "Check: Substitute x = 14
\n" ); document.write( "\"%283%2814%29-2%29%2F4%2814%29+=+3%2F14+%2B+1%2F2\" Simplify.
\n" ); document.write( "\"%2842-2%29%2F56+=+3%2F14+%2B+7%2F14\"
\n" ); document.write( "\"40%2F56+=+10%2F14\" Convert to equivalent fractions. Divide the top & bottom of the left side by 4.
\n" ); document.write( "\"10%2F14+=+10%2F14\"
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